How does slope-intercept form work?
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So let's say you have the equation y = (3/4)x + 5. First graph the y-intercept at point (0, 5). Then look at the slope, which is 3/4. From the point (0, 5) go up 3 points, then over to the right 4 points to graph your next point at (4, 8). You can also graph the line by doing the opposite: go 3 points down, then over to the left 4 points and graph a point there. If the slope is negative, say it's -2/3, go down 2 points and to the right 3 or up 2 points and the to the left 3.
The slope-intercept form is
y = mx + b
It's one possible form of a linear equation, i.e. an equation whose solution set is a straight line. In this form, x and y are variables. They are the coordinates of the general point (x, y) on the graph of the solution set. m represents the slope of the line and b represents the y-coordinate of the y-intercept. So, for instance,
y = 3x + 2
would have a slope of 3 (meaning that the line would rise three units for every one unit you moved to the right) and a y-intercept of (0, 2). The y-intercept is where the line crosses the y-axis. The x-coordinate of every point on the y-axis is 0. You can see that b is the y-coordinate simply by plugging 0 in for x:
y = 3x + 2 = 3(0) + 2 = 0 + 2 = 2
In the example
y = -4x + 2
the slope is -4, meaning that the graph drops four units for every one you move to the right, and again the y-intercept is (0, 2).
For
y = (1/2)x - 6
the slope is 1/2, meaning the graph rises one unit for every two you move to the right. The y-intercept is (0, -6).
Does that answer it?
Sections: Slope-intercept form, Point-slope form, Parallel and perpendicular lines
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Straight-line equations, or "linear" equations, graph as straight lines, and have simple variable expressions with no exponents on them. If you see an equation with only x and y â ” as opposed to, say x2 or sqrt(y) â ” then you're dealing with a straight-line equation.
There are different types of "standard" formats for straight lines; the particular "standard" format your book refers to may differ from that used in some other books. (There is, ironically, no standard definition of "standard form".) The various "standard" forms are often holdovers from a few centuries ago, when mathematicians couldn't handle very complicated equations, so they tended to obsess about the simple cases. Nowadays, you likely needn't worry too much about the "standard" forms; this lesson will only cover the more-helpful forms.
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I think the most useful form of straight-line equations is the "slope-intercept" form:
y = mx + b
This is called the slope-intercept form because "m" is the slope and "b" gives the y-intercept. (For a review of how this equation is used for graphing, look at slope and graphing.)
I like slope-intercept form the best. It is in the form "y=", which makes it easiest to plug into, either for graphing or doing word problems. Just plug in your x-value; the equation is already solved for y. Also, this is the only format you can plug into your (nowadays obligatory) graphing calculator; you have to have a "y=" format to use a graphing utility. But the best part about the slope-intercept form is that you can read off the slope and the intercept right from the equation. This is great for graphing, and can be quite useful for word problems. © Elizabeth Stapel 2006-2008
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Common exercises will give you some pieces of information about a line, and you will have to come up with the equation of the line. How do you do that? You plug in whatever they give you, and solve for whatever you need, like this:
Find the equation of the straight line that has slope m = 4
and passes through the point (â “1, â “6).
Okay, they've given me the value of the slope; in this case, m = 4. Also, in giving me a point on the line, they have given me an x-value and a y-value for this line: x = â “1 and y = â “6.
In the slope-intercept form of a straight line, I have y, m, x, and b. So the only thing I don't have so far is a value for is b (which gives me the y-intercept). Then all I need to do is plug in what they gave me for the slope and the x and y from this particular point, and then solve for b:
y = mx + b
(â “6) = (4)(â “1) + b
â “6 = â “4 + b
â “2 = b
Then the line equation must be "y = 4x â “ 2".
What if they don't give you the slope?
Find the equation of the line that passes through the points (â “2, 4) and (1, 2).
Well, if I have two points on a straight line, I can always find the slope; that's what the slope formula is for.
Now I have the slope and two points. I know I can find the equation (by solving first for "b") if I have a point and the slope. So I need to pick one of the points (it doesn't matter which one), and use it to solve for b. Using the point (â “2, 4), I get:
y = mx + b
4 = (â “ 2/3)(â “2) + b
4 = 4/3 + b
4 â “ 4/3 = b
12/3 â “ 4/3 = b
b = 8/3
...so y = ( â “ 2/3 ) x + 8/3.
On the other hand, if I use the point (1, 2), I get:
y = mx + b
2 = (â “ 2/3)(1) + b
2 = â “ 2/3 + b
2 + 2/3 = b
6/3 + 2/3 = b
b = 8/3
So it doesn't matter which point I choose. Either way, the answer is the same:
y = (â “ 2/3)x + 8/3
As you can see, once you have the slope, it doesn't matter which point you use in order to find the line equation. The answer will work out the same either way.
That's the best way.. at least for me.. to think about it.
y=4x+2
If X is 0, y=2
That's your y-intercept.
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