Solve the logarithmic equation?
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3^log3(1)=????
This is because x^0 = 1 and log(base x) 1 = 0 from the definition of a logarithm
so we get
x = 3 ^ [log (base 3) 1]
now we know that when log (base a) b = c
means that a^c = b
so for the logarithmic expression, we get
a = log (base 3) 1
3^a = 1
=> a = 0 since any number to the power of zero is 1
so we get
x = 3^(0)
x = 1
ANSWER
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